![Evaluate the following integrals:displaystyle int { cfrac { 2x+1 }{ (x+2){ ( x-3) }^{ 2 } } } dxquad Evaluate the following integrals:displaystyle int { cfrac { 2x+1 }{ (x+2){ ( x-3) }^{ 2 } } } dxquad](https://haygot.s3.amazonaws.com/questions/1668278_1665101_ans_fee6f126efe74fe6a56293f8028940a8.jpeg)
Evaluate the following integrals:displaystyle int { cfrac { 2x+1 }{ (x+2){ ( x-3) }^{ 2 } } } dxquad
![Disequazione: \frac{{{x}+{\left|{x}-{1}\right|}+{3}-{2}{\left({x }-{3}\right)}}}{{{\left|{x}\right|}-{\left|{x}^{2}-{1}\right|}}}\ge{0} Disequazione: \frac{{{x}+{\left|{x}-{1}\right|}+{3}-{2}{\left({x }-{3}\right)}}}{{{\left|{x}\right|}-{\left|{x}^{2}-{1}\right|}}}\ge{0}](https://www.skuola.net/news_foto/2017/10/dise_e6.jpg)
Disequazione: \frac{{{x}+{\left|{x}-{1}\right|}+{3}-{2}{\left({x }-{3}\right)}}}{{{\left|{x}\right|}-{\left|{x}^{2}-{1}\right|}}}\ge{0}
Sci-Pi - Simplify: (x-2)/(x²-1) - (x+1)/(x²-2x+1) Useful Links: Link to answer: https://scipipupil.blogspot.com/2020/09/simplify-x-2x-1-x1x-2x1-simplification.html Website: https://SciPiPupil.blogspot.com For Solutions Visit: https://scipitutor ...
![Equazioni esponenziali e logaritmiche: {2}\cdot \log{{x}}- \log{{\left({2}{x }+{1}\right)}}+ \log{{3}}= \log{{\left({x}-{2}\right)}} Equazioni esponenziali e logaritmiche: {2}\cdot \log{{x}}- \log{{\left({2}{x }+{1}\right)}}+ \log{{3}}= \log{{\left({x}-{2}\right)}}](https://www.skuola.net/news_foto/2017/10/equ_log_e3.jpg)